x^2+30x-75=0

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Solution for x^2+30x-75=0 equation:


Simplifying
x2 + 30x + -75 = 0

Reorder the terms:
-75 + 30x + x2 = 0

Solving
-75 + 30x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '75' to each side of the equation.
-75 + 30x + 75 + x2 = 0 + 75

Reorder the terms:
-75 + 75 + 30x + x2 = 0 + 75

Combine like terms: -75 + 75 = 0
0 + 30x + x2 = 0 + 75
30x + x2 = 0 + 75

Combine like terms: 0 + 75 = 75
30x + x2 = 75

The x term is 30x.  Take half its coefficient (15).
Square it (225) and add it to both sides.

Add '225' to each side of the equation.
30x + 225 + x2 = 75 + 225

Reorder the terms:
225 + 30x + x2 = 75 + 225

Combine like terms: 75 + 225 = 300
225 + 30x + x2 = 300

Factor a perfect square on the left side:
(x + 15)(x + 15) = 300

Calculate the square root of the right side: 17.320508076

Break this problem into two subproblems by setting 
(x + 15) equal to 17.320508076 and -17.320508076.

Subproblem 1

x + 15 = 17.320508076 Simplifying x + 15 = 17.320508076 Reorder the terms: 15 + x = 17.320508076 Solving 15 + x = 17.320508076 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-15' to each side of the equation. 15 + -15 + x = 17.320508076 + -15 Combine like terms: 15 + -15 = 0 0 + x = 17.320508076 + -15 x = 17.320508076 + -15 Combine like terms: 17.320508076 + -15 = 2.320508076 x = 2.320508076 Simplifying x = 2.320508076

Subproblem 2

x + 15 = -17.320508076 Simplifying x + 15 = -17.320508076 Reorder the terms: 15 + x = -17.320508076 Solving 15 + x = -17.320508076 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-15' to each side of the equation. 15 + -15 + x = -17.320508076 + -15 Combine like terms: 15 + -15 = 0 0 + x = -17.320508076 + -15 x = -17.320508076 + -15 Combine like terms: -17.320508076 + -15 = -32.320508076 x = -32.320508076 Simplifying x = -32.320508076

Solution

The solution to the problem is based on the solutions from the subproblems. x = {2.320508076, -32.320508076}

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